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increase retire page size

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This commit is contained in:
daan 2020-01-27 23:15:24 -08:00
parent 42586de104
commit 9c166d88f0
1 changed files with 4 additions and 2 deletions
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6
src/page.c
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@ -386,6 +386,8 @@ void _mi_page_free(mi_page_t* page, mi_page_queue_t* pq, bool force) {
_mi_segment_page_free(page, force, segments_tld);
}
#define MI_MAX_RETIRE_SIZE (4*MI_SMALL_SIZE_MAX)
// Retire a page with no more used blocks
// Important to not retire too quickly though as new
// allocations might coming.
@ -406,7 +408,7 @@ void _mi_page_retire(mi_page_t* page) {
// how to check this efficiently though...
// for now, we don't retire if it is the only page left of this size class.
mi_page_queue_t* pq = mi_page_queue_of(page);
if (mi_likely(page->xblock_size <= MI_SMALL_SIZE_MAX && !mi_page_is_in_full(page))) {
if (mi_likely(page->xblock_size <= MI_MAX_RETIRE_SIZE && !mi_page_is_in_full(page))) {
if (pq->last==page && pq->first==page) { // the only page in the queue?
mi_stat_counter_increase(_mi_stats_main.page_no_retire,1);
page->retire_expire = 16;
@ -421,7 +423,7 @@ void _mi_page_retire(mi_page_t* page) {
// free retired pages: we don't need to look at the entire queues
// since we only retire pages that are the last one in a queue.
void _mi_heap_collect_retired(mi_heap_t* heap, bool force) {
for(mi_page_queue_t* pq = heap->pages; pq->block_size <= MI_SMALL_SIZE_MAX; pq++) {
for(mi_page_queue_t* pq = heap->pages; pq->block_size <= MI_MAX_RETIRE_SIZE; pq++) {
mi_page_t* page = pq->first;
if (page != NULL && page->retire_expire != 0) {
if (mi_page_all_free(page)) {