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Use LLONG_MAX instead of std::numeric_limits<long long>::max() when constexpr is absent
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@ -1166,7 +1166,11 @@ private:
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static const std::intmax_t d1 = R1::den / gcd_d1_d2;
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static const std::intmax_t d1 = R1::den / gcd_d1_d2;
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static const std::intmax_t n2 = R2::num / gcd_n1_n2;
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static const std::intmax_t n2 = R2::num / gcd_n1_n2;
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static const std::intmax_t d2 = R2::den / gcd_d1_d2;
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static const std::intmax_t d2 = R2::den / gcd_d1_d2;
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#ifdef __cpp_constexpr
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static const std::intmax_t max = std::numeric_limits<std::intmax_t>::max();
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static const std::intmax_t max = std::numeric_limits<std::intmax_t>::max();
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#else
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static const std::intmax_t max = LLONG_MAX;
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#endif
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template <std::intmax_t Xp, std::intmax_t Yp, bool overflow>
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template <std::intmax_t Xp, std::intmax_t Yp, bool overflow>
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struct mul // overflow == false
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struct mul // overflow == false
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